
Example of the Method of Determination.
When iron wire is in circuit, deflection falls—(1) From. 200 to 103 for one direction; (2) from 200 to 176½ in opposite direction.
When the iron wire was removed, and a copper one substituted, the fall of deflection was—(1) From 200 to 101 for one direction; (2) from 200 to 101 for opposite direction.

On the addition of a carbon resistance of 8.5 ohms to the discharge circuit, the fall of the deflection was—(1) From 200 to 103; (2) from 200 to 176½.
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Since the fall of deflection is the same in the two cases, resistance of iron wire = 8.5 ohms + resistance of the copper, wire for that particular period. Now, from Lord Rayleigh's equations, the resistance of copper wire in rapidly alternating fields is given by R′ = √½p l R, where l = length of wire, and R is resistance of wire for steady currents. From knowledge of the period this may readily be calculated. The resistance of the iron wire is therefore known.
In order to determine the period very accurately, a plate condenser was used with ebonite as the dielectric. The S.I.G. of ebonite had been determined previously and found to be 2.2. The capacity of the condenser was found from calculation of the size of the plates to be 460 electrostatic units.
From knowledge of the data of the discharge circuit the self-inductance can be calculated. (See Lodge's “Experiments on Discharge of Leyden-jars,” Proc. Roy. Soc., June 4, 1891, p. 33.)
The self-inductance L = 4278;
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frequency n = 2π √LC
= 3.5 × 106;
and p = 2μn = 2.1 × 107.
The effect of the increase of diameter of wires on the self-inductance of the circuits is small, so that in all cases the number of oscillations per second will be taken as 3,500,000. When the resistances of iron wires of different sections were being determined a copper wire of as near as possible the diameter of the iron wire under consideration was placed in the circuit. In the case of an iron wire 0.22in. in diameter, a lead pipe took the place of the copper conductor.
After the calculated resistance of the copper wires for a frequency of 3,500,000 had been added to the carbon resistance placed in the circuit, the following is the table of resistances observed:—
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| Wire. | Diameter. | Resistance for Steady Currents. | Resistance for a Frequency of 3,500,000. | |
| In. | Ohms. | Ohms. | ||
| (1.) Soft iron | 0.011 | 8.5 | 14. | |
| (2.) Soft iron | 0.39 | 1.17 | 9.2 | |
| (3.) Steel pianoforte-wire | 0.32 | 1.59 | 10.7 | |
| (4.) Nickel wire | 0.043 | 0.59 | 7.2. | |
| (5.) Soft-iron wire | 0.145 | 0.07 | 4.9 | |
| (6.) Soft-iron wire | 0.222 | 0.032 | 4. |

It will be observed that for the soft-iron wire 0.222in. in diameter the resistance of the wire is 125 times its resistance for steady currents.
The wire 0.145in. in diameter is seventy times its ordinary resistance, and wire 0.039in, about eight times.
The general result of this investigation supports the theory of increase of resistance of conductors as the rapidity of the oscillations is increased.
The experiments here recorded receive additional confirmation from later investigations on the circular magnetization of iron.
It will be observed that the wire 0.011in. in diameter does not double its ordinary resistance for a frequency of 3,500,000, and the resistances increase more rapidly for increase of diameter than ordinary theory would lead-us to expect.
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Lord Rayleigh has shown that the resistance of a wire of permeability μ for rapidly-alternating fields is √½ μPlR, where R = resistance for steady currents.
Now, for wire of diameter 0.222in;
and substituting p = 2.1 × 107,
l = 377,
R = 0.032 ohm,
we get an equation for μ and it will be found that in this case μ = 121; and, if we thus determine μ for the different soft-iron wires, we get the following table:—
| Diameter. | Calculated Permeability. |
| 0.011in. | 5.8 |
| 0.039in. | 18 |
| 0.145in. | 87 |
| 0.222in. | 121 |
It will be observed that the apparent permeability of the wire increases proportionately to the radius. Where the radius of wire is increased twenty times, permeability is increased twenty times, and so on.
I am not aware that anything definite on this subject has been hitherto done; but the following approximate calculation possibly gives the true explanation:—
Consider a condenser charged with a quantity Q0 of electricity.
The maximum current of discharge J = pQ0, assuming no decrease in amplitude.
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Now, if this current be confined to a surface-skin of the conductor, the magnetic force, at a distance r from the centre, is given by H = 2J/r.

Now, this value of H at any point only depends on the current flowing external to that point; and, since the current is mainly confined to the surface, we may take r = radius of wire.
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H = 2pQ0/r = 2/r PCV0, where V0 is potential between knobs,
and C is capacity of condenser.
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As the spark-gap was 1/10in. in length, the difference of potential was as near as possible 10,000 volts. Substituting these values, it will be found that H = 18.8/r nearly.
For the first wire r = 0.011in. = 0.027cm.
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∴ H = 18.8/0.013 = 1,400 approximately;
and, taking B = 12,000, we get a value of
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μ = B/H = 9 approximately.
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The observed value is about 6; but the discrepancy between the two results is to be expected, and is due to the fact that the resistance of the iron is measured after a succession of discharges in the same direction, when, on account of the greater amplitude of the first half-oscillation, the inner part of the wire is practically saturated, and does not offer any considerable permeability when once the current has penetrated through the external skin, magnetized in the opposite direction by the second half-oscillation. The equations H = 2J/r and μ = B/H = Br/2J show that we should expect the permeability of the iron to vary as the radius of the wire, within, of course, the maximum limit of permeability of iron—i.e., about 3,000. The table given previously shows how closely the law is fulfilled in practice.
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Now, J = pQ0 = 1/√LC CV0, and V0 varies as the spark length d.
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∴ J ∝ √C/√L . d,
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and μ= Br/2J, and when the iron is saturated B may be takenas constant.
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∴ μ ∝ r√L/d√C.
Therefore increase of radius increases the permeability of iron in these fields, and the shorter the spark-gap the higher the permeability, and therefore the resistance.

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The resistance R′ for high frequencies = √½μ0plR.
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∴ R′ ∝ √½ r √L/d√C . l/√CL . l/r2.
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∝ 1/√rcd, where l is constant.
The resistance of iron wires in these fields varies inversely as the root of the radius, inversely as the root of the capacity, and inversely as the root of the spark-length, and is independent of the inductance of the circuit.
The increase of resistance of iron wires for rapidly-alternating currents has been ascribed to the concentration of the current on the surface of the conductor. There is also, of course, loss of energy by hysteresis on account of the magnetization and demagnetization of the iron wire. Although much more energy is absorbed in steel than in soft iron, due to hysteresis, the steel wire did not show any greater increase of resistance than the soft-iron wire. It seems, therefore, that the effect of hysteresis may be neglected as a, factor in determining the increase of resistance of wires.
It is possible that the absorption of energy due to hysteresis may be much greater for a frequency of several millions than for frequencies of 1,000; but it is a very difficult matter to separate the effects of induced currents from those of hysteresis in causing absorption of energy in an iron cylinder.
