
Art. LII.—Two Spherical Harmonic Relations.
[Read before the Philosophical Institute of Canterbury, 3rd September, 1902.]
The relations proved in this paper were given without distinct proof as following simply from the generalised form of four others which I discovered in working out the expressions* for the intensity of the magnetic force in the interior of coils of various lengths. They were, however, cut out by Professor Lamb, who very kindly communicated my paper to the Royal Society, as he did not see how they were obtained. This of itself causes me to think they may be new, and, as the original four are, I believe, new ones, hope in this direction is strengthened. I have known them for some years now, but as they follow simply from the four already published I had not up till now thought them worth publication. I have, however, been recently rather strongly advised to print them.
Using the notation of my previous paper, the original four are these:—
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
(1) d/dx Pσ/rσ+1 = 1/rσ+2d/dθ Pσ + 1
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
(2) d/dxrσPσ = rσ-1d/dθ Pσ − 1
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
(3) dι/dzι Pσ/rσ+1 = (σ + ι)!/σ! Pσ + i/rσ+ι+1
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
(4) di/dzιrσ Pσ = (− 1)ι σ!/(σ − ι)! rσ-i Pσ − i
Now, since the order of differentiation is indifferent, we have
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
dι/dzι/d/dx Pσ/rσ+1 = d/dzx/dι/dzι Pσ/rσ+1 (5)
Taking first the left-hand side of the equation and making use of (1) we have
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
di/dzι/d/dx Pσ/rσ+1 = di/dzι1/rσ+2 d/dθ Pσ + 1 (6)
Now, taking the right-hand side of (5) and using (3), it follows
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
d/dx/dι/dzi Pσ/rσ+1 = d/dx (σ + ι)!/σ! Pσ + i/rσ+ι+1
= (σ + ι)!/σι 1/rσ+ι+2 d/dθ Pσ + i + 1
[Footnote] * Roy. Soc. Proc., vol. lxiv., p. 193.

from (1). Hence
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
di/dzi 1/rσ+2 d/dθ Pσ + 1 = 1/rσ+i+2 (σ+1)!/σ! ddθ Pσ + i + 1
or, elevating one order,
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
dι/dzι (1/rσ+1 d/dθ Pσ) = 1/rσ+ι+1 σ!/(σ − 1)! ddθ Pσ + i (a)
which is the first of the two relations.
The second is established in a precisely similar manner.
Thus
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
d/dx di/dzι rσ Pσ = di/dzι d/dx dσ Pσ
By means of (4) the left-hand side becomes
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
d/dx di/dzι rσ Pσ = (− 1)i d/dx σ!/(σ − i)! rσ-i Pσ − ι
= (− 1)i σ!/(σ -ι)! rσ-i d/dθ Pσ − i − 1
from (2). For the right-hand side we have, using (2),
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
di/dzι d/dx r σ Pσ = dι/dzi (rσ-1 d/dθ Pσ − 1)
Hence
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
di/dzi (rσ-1 d/dθ Pσ − 1)= (− 1)i σ!/(σ − i)! rσi−1 d/dθ Pσ − i − 1
or, elevating one order,
[The section below cannot be correctly rendered as it contains complex formatting. See the image of the page for a more accurate rendering.]
dι/dzi (rσ d/dθ Pσ)= (− 1)i (σ + 1)!/σ! rσ-i d/dθ Pσ − i
which is the second relation.
